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Ruby 教程(四)
阅读量:4051 次
发布时间:2019-05-25

本文共 1547 字,大约阅读时间需要 5 分钟。

数组

=begin
#1, 基本数组
x = [1, 2, 3, 4, 5]
print "one is ", x [ 2 ] ,  "/n"
x[2] += 5
print "two is ", x [ 2 ] ,  "/n"
x[2] = "Fish " * 3
print "three is ", x [ 2 ] ,  "/n"
x = []
print "four is ", x ,  "/n"
x << "word "
print "five is ", x, "/n"
x << "Play "
x << "Fun "
print "fix is ", x , "/n"
print "seven is ", x.pop , "/n"
print "eight is ", x.pop , "/n"
print "nine is ", x.pop , "/n"
print "ten is ", x , "/n"
print "the length of x is ", x.length , "/n"
x = ["word ", "play ", "fun .", 2]
print "A_first is ", x, "/n"
print "A_second is ", x.join, "/n"  #join 把所有元素连接起来, 则形成一个大字符串
print "A_three is ", x.join(', '), "/n"  #join 可接受一个可选参数
#2, 字符串切分成数组
print "This is a test".scan(//w/).join(', ') , "/n"
print "short sentence. another. no more.".split(//./).inspect , "/n"
print "short sentence. another. no more.".split(//s+/).inspect , "/n"
#3. 数组迭代
[1, "test", 2, 3, 4].each {|element|
  print element.to_s + "_x", "/n"
}
[1, "test ", 2, 3, 4].collect {|element|
  print element*5 , "/n"
}
#4. 数组加法、串联
x = [1, 2, 3]
y = ["a ", "b ", "c "]
z = x + y
print z , "/n"
print z.inspect , "/n"
#5, 数组减法、区分
x = [1, 2, 3, 4, 5]
y = [1, 2, 3]
z = x - y
print z , "/n"
print z.inspect , "/n"
#6. 检查数组是否为空
x = []
print "x is empty!" if x.empty? 
print "/n"
#7. 检查数组是否含有某个元素
x = [1, 2, 3, 4, 5, "x"]
print "b_first is ", x.include?(x)
puts
print "b_second is ", x.include?("x")
puts
#8, 访问数组中第一个、 最后一个元素
x = [1, 2, 3, 4, 5, "x"]
print "c_first is ", x.first
puts
print "c_second is ", x. last
puts
=end
#9. 翻转数组中的数据
x = [1, 2, 3, 4, 5, "x"]
puts x.reverse.inspect

转载地址:http://nrcci.baihongyu.com/

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